I ask if i can calculate xor to all numbers in a specific range without using loop
for example if i have
start=3
end =3211233432145321;
the result start ^ start+1 ^ start+2 ^ start+3.........end-1^end
Thanks in advanced.
I ask if i can calculate xor to all numbers in a specific range without using loop
Finally,
you mention that you need only last 4 numbers so to calculate f(x)
f(x)=(x-3)^(x-2)^(x-1)^(x)
i test it by using this function vs bruteforce solution but the result different.
I wrote C++ code for this: https://github.com/liruqi/topcoder/blob/master/leetcode/exclusive-or-of-numbers-range.cpp