1_Hypex_'s blog

By 1_Hypex_, history, 7 months ago, In English

As an assignment, students at HackerLand High School are to find a subsequence using two strings by performing the below-mentioned operation. Given two strings firstString of length n and secondString of length m, the goal is to make secondString a subsequence of firstString by applying the operation any number of times. In one operation, any single character can be removed from the secondString. The goal is to find the minimum possible difference value which is calculated as: | maximum index of all the characters removed from the string secondString | — |minimum index of all the characters removed from the string secondString |+ 1. Removing a character from secondString does not affect the indices of the other characters and an enmpty string is always a subsequence of firstString.

Example n= 10, first-string = HACKERRANK m=9, secondString = HACKERMAN Remove the character at index 7 to change second string to "HACKERAN", a subsequence of firstString. The difference value is 7 -7+1 =1. Return 1.

Constraints " 1<=n<=10^5 " 1<=m<=10^5

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7 months ago, # |
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Auto comment: topic has been updated by 1_Hypex_ (previous revision, new revision, compare).

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7 months ago, # |
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Auto comment: topic has been updated by 1_Hypex_ (previous revision, new revision, compare).

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7 months ago, # |
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ig we can binary search on difference value's.

For a fixed difference we can check if possible or not in O(n) using dp

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    7 months ago, # ^ |
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    I also thought about a similar approach. But I can think about it in O(n*m*logm). Can you slightly elaborate on your approach? Thanks.

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      7 months ago, # ^ |
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      dp1[i] = maximum j such that b[i:m] is a subsequence of a[j:n]

      dp2[i] = minimum j such that b[1:i] is a subsequence of a[1:j]

      removing b[i:j] will be valid iff dp1[j+1] > dp2[i-1]

      This feels correct but idk might be wrong

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        7 months ago, # ^ |
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        It makes sense. Thank you for sharing.