Today will be CF #313. I will take part in it and I will do at least 20*sqrt(max(0,myRatingLoss)) push-ups in 24h. Wish me good luck.
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myRatingLoss = newRating — OldRaing?
oldRating — newRating of course :D
Delete sqrt function and you will be strong boy.
I expect some proof like video or something :]
sure
We can go deeper. How about Fibonacci(20*sqrt(max(0,myRatingLoss)))? (Of course this is just a joke)
So if myRatingLoss is big enought the fibunacci number will overflow the data type and the number will be < 0.
...or it will be undefined behaviour :P
If you write "this is a joke" in parenthesis that joke loses the sense ;)
Waiting for proof. :P
So judging by your results, we'll be seeing some imaginary push-ups?
P.S.
Oh never mind, you got MAX(0,ratingLoss). I would've liked to see imaginary push-ups :D
You can't see imaginary ones because they're not real. (That's how it works with imaginary quantities in physics, at least.)
Well, trying to give video proof of his imaginary push-ups would've been interesting
Are they perpendicular to real push-ups?
But fortunately I wrote sqrt(max(0,loss)) so it's real.
You can't see them, but you can imagine them.
I get 7-th place! Motivation is a good thing. Or fear. Or luck.
Push-ups? Maybe next time.
Only people whom are sure that 0 is greater than their rate loss will accept these type of challenges! Not a unstable one like me :D
btw. nice rating graph
if it was myRatingLoss = newRating — OldRaing, you would make push-ups
it would be bad naming though
Unstable? Look at my graph. :P Your is really nice.
What an amazing idea. I'll do the same for every contest.
You after one year