I solved TopBiologist by recursion. I want to know if there is any iterative approach? We will need to run loop 6 times to generate sequence of length 6. Is there any shorter way to do this?
I solved TopBiologist by recursion. I want to know if there is any iterative approach? We will need to run loop 6 times to generate sequence of length 6. Is there any shorter way to do this?
№ | Пользователь | Рейтинг |
---|---|---|
1 | tourist | 3690 |
2 | jiangly | 3647 |
3 | Benq | 3581 |
4 | orzdevinwang | 3570 |
5 | Geothermal | 3569 |
5 | cnnfls_csy | 3569 |
7 | Radewoosh | 3509 |
8 | ecnerwala | 3486 |
9 | jqdai0815 | 3474 |
10 | gyh20 | 3447 |
Страны | Города | Организации | Всё → |
№ | Пользователь | Вклад |
---|---|---|
1 | maomao90 | 174 |
2 | awoo | 164 |
3 | adamant | 163 |
4 | TheScrasse | 159 |
5 | nor | 157 |
6 | maroonrk | 155 |
7 | -is-this-fft- | 152 |
8 | Petr | 146 |
8 | orz | 146 |
10 | BledDest | 145 |
Название |
---|
It's similar to converting numbers into the radix 4.
Thanks. Can we write i th element of an integer array like you wrote for string?
You wrote
s += "ACGT"[x % 4]
I wrote this and got compilation error
for(int i=0;i<4;i++) cout<<{1,2,3,4}[i];
I have found an interesting solution without recursion.