Use priority_queue instead, it's faster and more useful. A nice implementation can be found at https://cp-algorithms.com/graph/dijkstra_sparse.html

https://codeforces.com/blog/entry/70237

Why i am getting tle for two test cases below is the code could someone tell me what to do

void solve(vector<node>adj[],int n) {
    priority_queue<pair<ll,ll>,vector<pair<ll,ll>>,greater<pair<ll,ll>>>pq;
    vector<ll>dist(n,LLONG_MAX);
    dist[1] = 0;
    pq.push({0,1});

    while(not pq.empty()) {
        ll u =pq.top().second;
        pq.pop();
        
        for(auto i:adj[u]) {
            if(i.des == 1) continue;
            ll v = i.des;
            ll w = i.weight;
            if(dist[u]+w <dist[v]) {
                dist[v] = dist[u] + w;
                pq.push({dist[v],v});
            }
        }
    }

    loop(i,1,n) {
        cout<<dist[i]<<" ";
    }
}

use visited array to ensure not visit same node again which is already minimum.