def solve(n, x, lst):
dp = []
for i in range(n+1):
temp = [1] + [0]*x
dp.append(temp)
for i in range(1, n+1):
for j in range(1, x+1):
dp[i][j] = (dp[i][j] + dp[i-1][j]) % mod
if j - lst[i-1] >= 0:
dp[i][j] = (dp[i][j] + dp[i][j - lst[i-1]]) % mod
for i in dp: print(i)
return dp[n][x]
n, x = list(map(int, input().split()))
lst = list(map(int, input().split()))
print(solve(n, x, lst))
...
The dp can be 1 dimensional, let c[] be the coins and x the sum, then dp[x] is the answer: